Question

detetermina nr x din egalitati a) 700-[400-(300-x)]=500 b)600-[300-(25+x)]=500

Answer 1

700-[400-(300-x)=500
[400-(300-x)=700-500
[400-(300-x)=200
300-x=400-200
300-x=200
x=300-200
x=100
Verificare:700-[400-(300-100)
700-[400-200]=
700-200=500

b)600-[300-(25+x)]=500
[300-(25+x)]=600-500
[300-(25+x)]=100
25+x=300-100
25+x=200
x=200-25
x=175
Verificare:600-[300-(25+175)]=
600-[300-200]=
600-100=500