Question

Diagonala unui patrat este 10 radical 3 .Afla aria si perimetrul.

Answer 1

$d = 10 \sqrt{3}$

$d = l \sqrt{2}$

$l \sqrt{2} = 10 \sqrt{3}$

$l = \frac{10 \sqrt{3} }{ \sqrt{2} }$

$l = \frac{10 \sqrt{6} }{2}$

$l = 5 \sqrt{6}$

$A = {l}^{2}$

$A = {(5 \sqrt{6}) }^{2}$

$A = 150$

$P = 4l$

$P = 4 \times 5 \sqrt{6}$

$P = 20 \sqrt{6}$