Question

Diferenta a 2 nr naturale e 139 impartind nr mai mare la dublul nr mai mic obtinem rest 6 si cat 10

Answer 1

a-b = 139

a : 2b = 10 r 6 <=> a = 20b +6

20b+6-b = 139 <=> 19b = 139-6 => 19b = 133

b = 133:19 => b = 7

a = 20b+6 = 20·7+6 = > a =146

146: 14 = 10 rest 6 , corect

Answer 2

a-b = 139 ; a > b ; a:2b = cat 10 rest 6 ; a=20b+6 ; (teorema impartirii cu rest), inlocuim a

20b+6-b = 139, 19b=139-6 = 133 ; b=133:19 = 7 ; a= 139+7 = 146 ;