Question

Din 3,92 g compus organic la ardere rezulta 6720 ml CO2 . Continutul de carbin al compusului organic este?

Answer 1

n = m/M = V/Vm => m = 44×6,72/22,4 = 13,2g CO2

%C = 300a/11s = 300×13,2/11×3,92 = 91,836

sau

44g CO2.................12g C
13,2g CO2...........x = 3,6g C

3,92g c.o.................3,6g C
100g....................x = 91,836%