Question

Din amidonul obtinut se preleveaza o proba .Calculează masa de amidon supusa hidrolizei,daca s au obtinut 2,16 g argint,la oxidarea C6H12O6

Answer 1

    Z                                        1.8

(C6H10O5)n  +nH2O →nC6H12O6

     162n                             nx180

      Y                                                              2,16

C6H12O6 +2[Ag(NH3)2]   → C6H12O7 + 2Ag↓ +   4NH3+ H20

 180                                                              2X108

 

 

               Y=2,16X180/2X108

Y=1.8g  alfa glucoza

Z=1,8x162n/nx180

Z=1,62 g amidon