Question

dintr-un depozit s-a livrat intr-o zi 3/10 din cantitatea de marfa,apoi inca 0,8 din rest ramanand 252 tone de marfa. cate tone de marfa erau la inceput si cat s-a livrat in cele 2 zile?

Answer 1

Prima,zi=3/10
A,doua,zi=8/10x7/10=56/100
3x/10+56x/100+252=x
30x+56x+25200-100x=0
25200=14x
x=1800tone,in,total
In,prima,zi,s-au,livrat:1800x3/10=540,tone
In,a,doua,zi,s-au,livrat:(1800-540)x8/10=1008,tone
Au,ramas,252,tone

Verif:540+1008+252=?1800
1800=1800(A)

Answer 2

Prima,zi=3/10
A,doua,zi=8/10x7/10=56/100
3x/10+56x/100+252=x
30x+56x+25200-100x=0
25200=14x
x=1800tone,in,total
In,prima,zi,s-au,livrat:1800x3/10=540,tone
In,a,doua,zi,s-au,livrat:(1800-540)x8/10=1008,tone
Au,ramas,252,tone
sper ca te-am ajutat