Question

Distanta dintre AB este de 60km. In sens opus de cele doua localitati se deplaseaza doi biciclisti cu V1=4m/s si V2=6m/s.

sa se calculeze:
a) timpul de intalnire
b) Distanta parcursa de fiecare biciclist pana la punctul de intalnire

Answer 1

60km = 60000m
4t+6t=60000
10t=60000
t=6000s
4*6000=24000 m(primul biciclist)
6*6000=36000 m(al 2 lea biciclist)

Answer 2

[tex]\tt Se~da:\\ \\ d=60km=60000m\\ \\ v_{1}=4 \frac{m}{s}\\ \\ v_{2}=6 \frac{m}{s}\\ \\ a)t=?s\\ \\ b)d_{1}=?m;~d_{2}=?m\\ \\ \\ [/tex]


[tex]\tt Formule:\\ \\ a)t=\frac{d}{v}\\ \\ v=v_{1}+v_{2} \Rightarrow t=\frac{d}{v_{1}+v_{2}}\\ \\ \\ b)t_{1}=t_{2}=t\\ \\ d_{1}=v_{1} \times t\\ \\ d_{2}=v_{2} \times t\\ \\ \\ Calcule:\\ \\ a)t=\frac{60000}{4+6}=6000s\\ \\ \\ b)d_{1}=4 \times 6000=24000m\\ \\ d_{2}=6 \times 6000=36000m\\ \\[/tex]