Question

Distanta dintre punctele A(1,2) SI B(5,-1) este egala cu:

Answer 1

AB=$\sqrt{(XB-XA) ^{2} +(YB-YA) ^{2} }$

AB=$\sqrt{(5-1) ^{2} +(-1-2) ^{2} } = \sqrt{4 ^{2} +(-3) ^{2} } = \sqrt{16+9} = \sqrt{25} =5$