Question

doar 5 am nevoie urgent va rog face ti l pe o foaie complex si dau coroana dau 90 de pcte

Answer 1

$\frac{x^2 + 2x - 3}{x^2 + x - 6 } * \frac{x^2 + 2x -8}{x^2+4x-5} + \frac{1}{x+5}$

$\frac{x^2+3x-x-3}{x^2+3x-2x-6} * \frac{x^2+4x-2x-8}{x^2+5x-x-5} + \frac{1}{x+5}$

$\frac{x(x+3)-(x+3)}{x(x+3)-2(x+3)} * \frac{x(x+4)-2(x+4)}{x(x+5)-(x+5)} + \frac{1}{x+5}$

$\frac{(x+3)(x-1)}{(x+3)(x-2)} * \frac{(x+4)(x-2)}{(x+5)(x-1)} + \frac{1}{x+5}$

$\frac{x+4}{x+5} + \frac{1}{x+5} = \frac{x+4+1}{x+5} = \frac{x+5}{x+5} = 1$