Question

Doar 6.0.1 urgent!!! Dau coroana.

Answer 1

$A=\frac{2017*1+1}{2017} +  \frac{2017*2+2}{2017} + ... + \frac{2017 * 2016 + 2016}{2017} = \frac{1(2017+1) + 2(2017+1)+...+2016(2017+1)}{2017}=\frac{\frac{2016 * 2017}{2}*2018}{2017}=\frac{1008 * 2017 * 2018}{2017}=1008*2018$

Bafta la olimpiada, chiar daca este peste 4 luni ;)))

Answer 2

1+2+3+....+2016=2017•2016:2
=2017•1008
=2013316
sincer nu stiu daca e corect dar vezi si tu .....