Question

doar a si f de la penultimu exercitiu

Answer 1

f)
=(39/1000):{(1/20)[(231/100) :(77/1000)]}-4,617=

=(39/1000):{(1/20)[(231/100)x(1000/77)]}-4,617=

=(39/1000):[(1/20)(3x10)]-4,617=

=(39/1000):(3/2)-4,617=

=(39/1000)x(2/3)-4,617=

=26/1000 +4617/1000=

=4643/1000=4,643

a)
=(-2/3)x(2008/2013)-(2/3)x(5/2013)=

=factor comun (-2/3)(1/2013)=

=(-2/3)(1/2013)(2008+5)=

=(-2/3)(1/2013)x2013=

=-2/3