Question

Doar A.Va rog este urgent!

Answer 1

Sa se efectueze :
A. a) 5^3/2×125^1/2×5^4/5×25^–0,4
=5^3/2×5^3/2×5^4/5×(1/25)^4/10
=5^6/2×5^4/5×(1/25)^2/5
=5³×5^4/5×1/(5²)^2/5
=5³×5^4/5×1/5^4/5
=5³×1
=125

b) 81^–3/4×27^–2/3×(1/0,(3))^5
=(3⁴)^–3/4×(3³)^–2/3×1/(3/9)^5
=3^4×(–3)/4×3^3×(–2)/3×1/(1/3)^5
=3^–3×3^–2×1×3^5
=3^–3–2+5
=3^–5+5
=3^0
=1

c) 3^4/3×9²×(27)^–5/6×3^–3/2
=3^4/3×(3²)²×(3³)^–5/6×3^–3/2
=3^4/3×3⁴×3^–5/2×3^–3/2
=3^(4+12)/3×3^(–5–3)/2
=3^16/3×3^(–4)
=3^(16–12)/3
=3^4/3
=³√3⁴

d) (1/3)^5/6×9^3/2×(2/54)^–2/3×3^–1/6
=1/(3)^5/6×(3²)^3/2×1/(3³)^–2/3×3^–1/6
=1/3^5/6×1/3^–3×3^–2×3^–1/6
=1/3^5/6×3³×3^(-2)×1/3^1/6
=1/3×3³×3^(–2)
=3²×3^(-2)
=3^0
=1

^– înseamnă la puterea
/–inseamna supra