Question

Doar b Dau coroana urgent va rog

Answer 1

Răspuns: $\Large\boxed{\bf 1 }$

$\bf~~~$

$\large \bf a) ~\bigg[\bigg(\dfrac{1}{2}\bigg)^{3} -\bigg(\dfrac{1}{6}\bigg)^{3}\bigg] \cdot \dfrac{128-20^{1}}{65:5} =$

$\large \bf \bigg(\dfrac{1^{3}}{2^{3}} -\dfrac{1^{3}}{6^{3}}\bigg) \cdot \dfrac{108}{13} =$

$\large \bf \bigg(\dfrac{1}{8} -\dfrac{1}{216}\bigg) \cdot \dfrac{108}{13} =$

$\large \bf \bigg(\dfrac{27\cdot 1}{216} -\dfrac{1}{216}\bigg) \cdot \dfrac{108}{13} =$

$\large \bf \dfrac{27-1}{216} \cdot \dfrac{108}{13} =$

$\large \bf \dfrac{26}{216} \cdot \dfrac{108}{13} =$

$\large \bf \dfrac{\not26}{\not216} \cdot \dfrac{\not108}{\not13} =$

$\large \bf \dfrac{2}{2} \cdot \dfrac{1}{1} =$

$\large\boxed{\boxed{\bf 1 }}$

==pav38==