Question

DOAR CELE ÎNCERCUITE VAAAA ROOOG DAU COROANA

Answer 1

 
3x+9>=3(x+1)+6
3x+9>=3x+3+6
3x+9>=3x+9
x=1

5x+3<=2(2x-7)+x+17
5x+3<=4x-14+x+17
5x+3<=5x+3
x=1



5(x+1)<5(x-1)+10
5x+5<5x-5+10
5x+5<5x+5
5x<5x  nu are solutii este imposibil

3(x+2)<3(x-1)+9
3x+6<3x-3+9
3x+6<3x+6
3x<3x   nu are solutii

exercitiul 17 rezolvare    x^2 inseamna la puterea a doua

(x+1)^2<x(x+3)+5
x^2+2x+1<x^2+3x+5           
3x-2x>-4
x>-4                        x apartine -5 ....infinit

(2x+3)^2>2x(2x+5)+1
4x^2+12x+9>4x^2+10x+1
12x-10x>-9+1
2x>-8
x>-4

x(x+1)-6>=(x-2)^2
x^2+x-6>=x^2-4x+4
5x>=10
x>=2

x(4x+5)<(2x-1)^2+8
4x^2+5x< 4x^2-4x+1+8
5x+4x<9
9x<9
x<1