Question

DOAR EX 5! Va rog, rapid <3

Answer 1

          Xg          60g
         MgCO3 +2HCl=MgCl2 +CO2 +H2O
        84g           2.36,5g



MMgCO3=24+12+3.16=84
MHCl=1+35,5=36,5

In react.chimica ,din sol. react. numai  md

c=md.100:ms
md=c.ms:100
md=20.300:100=60 g HCl
Acum se calc.  x din ecuatie
x=84.60:2.36,5=69,04 g MgCO3 (de puritate 80 la suta)

100 g MgCO3------------80 g MgCO3 pur
y g  -------------------------69,04 g
y=100.69,04:80=86,3 g MgCO3 total


sau calculezi  folosind formula puritatii
p=mt.100:mp
mp=mt.100:p=69,04.100:80=86,3 g