Question

doar exercitiile incercuite.

Answer 1

x°y=xy-2x-2y+6

5) x°x°x=10

x°y=(x-2)(y-2)+2

x°x=(x-2)(x-2)+2  =$(x-2)^2+2$

x°x°x=$(x-2)^2+2$°x= a°x

(a-2)(x-2)+2=   ($(x-2)^2+2-2$(x-2)+2 = $(x-2)^3+2$

[tex](x-2)^3+2=10 (x-2)^3+2-10=0 (x-2)^3-8=0 (x-2)^3=8 (x-2)^3=2^3 x-2=2 x=4[/tex]