Question

Doar exercitiul 2 va rogg habar n am ❤️

Answer 1

A=(3+√2+√3+2√2+2√3)/(1+√2+√3)

A=(3+3√2+3√3)/(1+√2+√3)

A=3(1+√2+√3)/(1+√2+√3)

A=3

Answer 2

$\it \sqrt8=\sqrt{4\cdot2} =2\sqrt2\\ \\ \sqrt{12}= \sqrt{4\cdot3} =2\sqrt3$

$\dfrac{3+\sqrt2+\sqrt3+2\sqrt2+2\sqrt3}{1+\sqrt2+\sqrt3} =\dfrac{3+3\sqrt2+3\sqrt3}{1+\sqrt2+\sqrt3} =\dfrac{3(1+\sqrt2+\sqrt3)}{1+\sqrt2+\sqrt3}=3$∈ℕ