Question

Doar exercitiul 5 in fiecare poza . 0fer 98 de puncte .

Answer 1

5. 4(2x-1)²-9(x+1)²=(x-5)(7x+1)
4(4x²-4x+1)-9(x²+2x+1)=7x²+x-35x-5
16x²-16x+4-9x²-18x-9=7x²-34x-5
7x²-34x-5=7x²-34x-5
x ∈ R

5. √3-3/2 - 1/1+√3
√3-3/2 = 1-√3/-2
√3-3/2 = 1-√3/2
(√3-3+1-√3)/2 = (-2)/2 = -1


5. E(x) = ( x²+4x+3/x+1 - 4 ) : (x-1) 
E(x) = (x²+3x+x+3/x+1 - 4) : (x-1)
E(x) = (x*(x+3)+x+3/x+1 - 4):(x-1)
E(x) = ((x+1)(x+3)/x+1 -4):(x-1)
E(x) = (x+3-4):(x-1)
E(x) = x+3-4/x-1 
E(x) = x-1/x-1
E(x) = 1


5. a=(√3+√2)(5-√6)+(√2-1)^2-3√3
a=5√3-√18+5√2-√12+2-2√2+1-3√3
a=5√3-3√2+5√2-2√3+2-2√2+1-3√3
a=0+0+3
a=3

Answer 2

(√3-3)/2 - 1/(1+√3)=
=(√3-3)/2 - 1 ×(1 - √3) / (1+√3)(1-√3)=
=(√3-3)/2 - (1-√3)/(1-3)=
= (√3-3)/2 + (1- √3)/2=
= -2/2=
=- 1



5.
 E(x) = ( x²+4x+3/x+1 - 4 ) : (x-1) 
E(x) = (x²+3x+x+3/x+1 - 4) : (x-1)
E(x) = (x×(x+3)+x+3/x+1 - 4):(x-1)
E(x) = ((x+1)(x+3)/(x+1-4):(x-1)
E(x) = (x+3-4):(x-1)
E(x) = x+3-4/x-1 
E(x) = x-1/x-1
E(x) = 1


5.
a=(√3+√2)(5-√6)+(√2-1)²-3√3
a=5√3-√18+5√2-√12+2-2√2+1-3√3
a=5√3-3√2+5√2-2√3+2-2√2+1-3√3
a=0+0+3
a=3

5)
Aplicam formula ( a - 1)² = a² - 2×a×1 + 1²= a² - 2a + 1 4(2 x - 1)²- 9( x + 1)²=(x- 5)( 7 x + 1)


4(4 x²- 4 x +1) -  9(x²+ 2 x + 1)=7 x² + x - 35 x-5
16 x²- 16 x + 4 - 9 x²- 18 x - 9=7 x² - 34 x - 5
7 x² - 34 x - 5 = 7 x²- 34 x - 5