Question

Doar partea cu fractia​

Answer 1

$\it \frac{2(\sqrt{7} + \sqrt{5} ) }{(\sqrt{7} + \sqrt{5} )( \sqrt{7} - \sqrt{ 5}) } = ~^{\sqrt{7} + \sqrt{5}) } \frac{2}{\sqrt{7} - \sqrt{5} } = \frac{2(\sqrt{7} + \sqrt{5}) }{(\sqrt{7})^{2} - (\sqrt{5})^{2} } = \frac{2(\sqrt{7} + \sqrt{5})}{7 - 5} = \frac{\not 2(\sqrt{7} + \sqrt{5})}{\not 2} \\ \\ = \sqrt{7} + \sqrt{5}$

Answer 2

Răspuns:

    $\sqrt{7}+\sqrt{5}$

Explicație pas cu pas:

    $\frac{2(\sqrt{7}+\sqrt{5})}{(\sqrt{7}+\sqrt{5})(\sqrt{7}-\sqrt{5})}$

    $\frac{2(\sqrt{7}+\sqrt{5})}{\sqrt{7^{2}}-\sqrt{5}^{2}}$

    $\frac{2(\sqrt{7}+\sqrt{5})}{7-5}$

    $\frac{\not2(\sqrt{7}+\sqrt{5})}{\not2} = \boxed {\sqrt{7}+\sqrt{5}}$