Question

doar punctele a si b de la exercițiul 9​

Answer 1

Răspuns:

Explicație pas cu pas:

   

Answer 2

Explicație pas cu pas:

a)

$\bigg( \dfrac{2}{ \sqrt{12} } - \dfrac{15 ^{(5} }{5 \sqrt{3} } + \dfrac{9}{ \sqrt{27} }\bigg) - \bigg( \dfrac{24}{ \sqrt{48} } + \dfrac{45}{ \sqrt{75} } + \dfrac{48 ^{(8} }{8 \sqrt{3} }\bigg) =$

$= \bigg( \dfrac{2^{(2}}{2 \sqrt{3} } - \dfrac{3}{\sqrt{3} } + \dfrac{9^{(3}}{3\sqrt{3} }\bigg) - \bigg( \dfrac{24^{(4}}{4\sqrt{3} } + \dfrac{45^{(5}}{5\sqrt{3} } + \dfrac{6}{\sqrt{3} }\bigg)$

$= \bigg( \dfrac{1}{\sqrt{3} } - \dfrac{3}{\sqrt{3} } + \dfrac{3}{\sqrt{3} }\bigg) - \bigg( \dfrac{6}{\sqrt{3} } + \dfrac{9}{\sqrt{3} } + \dfrac{6}{\sqrt{3} }\bigg)$

$= \dfrac{1}{\sqrt{3} } - \dfrac{6 + 9 + 6}{\sqrt{3} } = \dfrac{1 - 21}{\sqrt{3} } = - \dfrac{20^{(\sqrt{3}}}{\sqrt{3} }$

$= - \dfrac{20 \sqrt{3} }{3}$

b)

$\bigg( \dfrac{5}{ \sqrt{2} } - \dfrac{3 \sqrt{2} }{4}\bigg) - \bigg( \dfrac{12 \sqrt{2}^{(3} }{6} + \dfrac{18^{(3}}{3 \sqrt{2}}\bigg) =$

$= \bigg( \dfrac{^{2 \sqrt{2})} 5}{ \sqrt{2} } - \dfrac{3 \sqrt{2} }{4}\bigg) - \bigg( \dfrac{4 \sqrt{2}}{2} + \dfrac{^{ \sqrt{2} )} 6}{ \sqrt{2} }\bigg)$

$= \dfrac{10 \sqrt{2} - 3 \sqrt{2} }{4} - \dfrac{4 \sqrt{2} + 6 \sqrt{2} }{2} = \dfrac{7 \sqrt{2}}{4} - \dfrac{^{2)} 10 \sqrt{2}}{2}$

$= \dfrac{7 \sqrt{2} - 20 \sqrt{2} }{4} = - \dfrac{13 \sqrt{2} }{4}$