Question

doar punctele c. d. si f. ​

Answer 1

Răspuns:

c) $(\sqrt{225} +\sqrt{169}) : (-\sqrt{16} )$ = (15+13) : (-4) = 28:(-4)= -7

d) $\sqrt{(-5)^{4} }-\sqrt{10^2} +\sqrt{121}$ = $\sqrt{625} -\sqrt{100} +11$ = 25-10+11= 26

f) $\frac{\sqrt{144}}{\sqrt{64} } +\frac{\sqrt{529} }{2} = \frac{12}{8} +\frac{23}{2} = \frac{12}{8} +\frac{92}{8} =\frac{104}{8}$ = 13

Succese!)

Answer 2

Explicație pas cu pas:

$( \sqrt{225} + \sqrt{169} ) \div ( - \sqrt{16}) = (15 + 13) \div ( - 4) = 28 \div ( - 4) = - 7$

$\sqrt{ {( - 5)}^{4} } - \sqrt{ {10}^{2} } + \sqrt{121} = \sqrt{ {5}^{4} } - 10 + 11 = {5}^{2} + 1 = 25 + 1 = 26$

$\frac{ \sqrt{144} }{ \sqrt{64} } + \frac{ \sqrt{529} }{2} = \frac{12}{8} + \frac{23}{2} = 1.5 + 11.5 = 13$