Question

Doi conductori ohmici ale caror rezistente sunt R1=100Ohmi si R2=1000ohmi sunt legati in paralel.La bornele lor se aplica o tensiune U=200V.
a)Calculeaza I1 si I2;
b) Determina si compara puterile electrice ale celor doi conductori.
Interpreteaza rezultatul!

Answer 1

I1=U/R1=200 V/100 ohmi=20 A
I2=U/R2=200 V/1000 ohmi=0,2 A

P=R×I²= R1×I²=100×4=400 W
P2=R2×I²=1000×0,04=40 W

Answer 2

a) I1= U/R1=200/100=2 A iar I2=U/R2=200/1000=0,2 A
b) P=R*I^2  
P1=R1* I1^2=100*4=400W
P2=R2*I2^2=1000*0,04=40W