Question

doi la puterea 1 ori doi la puterea 2 ori......2 la puterea 45

Answer 1

$2^1*2^2*2^3*.....*2^{45}=2^{1+2+3+...+45} \\ 1+2+3+...+45= \frac{45*46}{2}= 1035 \\ \\ 2^1*2^2*3^3...*2^{45}=2^{1035}$

Formule folosite:

$a^x*a^y=a^{x+y} \\ 1+2+3+....+n= \frac{n*(n+1)}{2}$