Question

Doi muncitori, depasind norma de lucru, primul cu 20% si al doilea cu 15%, realizeaza 1995 de piese. In à doua luna, primul muncitor a realizat numai 90% din norma, iar al doilea a depasit norma cu 10%, realizand impreuna 1710 piese. Care a fost norma fiecarui muncitor?

Answer 1

A=norma muncitor 1
b=norma muncitor 2
120%a+115%b=1995
90%a+110%b=1710

120a+115b=199500
9a+11b=17100

24a+23b=39900
9a+11b=17100      b=(17100-9a)/11
24a+23×(17100-9a)/11=39900
264a+393300-207a=438900
57a=45600
a=800 piese muncitor 1
b=(17100-9×800)/11=900 piese muncitor 2.Bafta!

Answer 2

120/100*x+115/100*y=1995
90/100*x+110/100*y=1710

9/10*x+11/10*y=1710
9*x+11*y=17100
9x=17100-11y
X=(17100-11y)/9


120*x+115*y=199500
120*(17100-11y)/9+115y=199500
(2052000-1320y)/9+1035y/9=1795500/9
2052000-1795500=1320y-1035y
256500=285y
Y=900

X=(17100-9900)/9
X=800