Question

dupa rationalizare fractia 9 supra radical din 3 devine

Answer 1

     
$\displaystyle \frac{9}{ \sqrt{3}} =\frac{9 \times \sqrt{3}}{ \sqrt{3} \times \sqrt{3}}= \frac{9 \sqrt{3}}{ 3} = \boxed{3\sqrt{3}}$

Answer 2

$^{ \sqrt{3}) } \frac{9}{ \sqrt{3} } = \frac{9 \sqrt{3} }{3} =3 \sqrt{3}$