Question

e dau numerele 3,23(8) şi 2,3(12).
CERINȚA
Media aritmetică a numerelor date este egală cu:

Answer 1

$3.23(8) = \frac{3238 - 323}{900} = \frac{2915}{900} \\ \\ 2.3(12) = \frac{2312 - 23}{990} = \frac{2289}{990}$

$\color{green}media \: aritmetica = \frac{a + b}{2}$

$( \frac{2915}{900} {}^{(5} + \frac{2259}{990} {}^{(9} ) \div 2 = \\ \\= ( {}^{110)} \frac{583}{180} + {}^{180)} \frac {251}{110} ) \div 2 = \\ \\ = \frac{64130 + 45180}{19800} \div \frac{2}{1} =\\ \\ = \frac{109310}{19800} \times \frac{1}{2} = \\ \\= \frac{109310}{39600} =\frac{10931}{3960}$

=2,760(35)

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