Question

e de x =(x-1)'2-(x-2)'2+(1-x)'2-(2-x)'2

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Answer 1

Răspuns:

E(x) = (x-1)²-(x-2)²+(1-x)²-(2-x)²

(x-1)²=x²-2x+1

(x-2)²=x²-4x+4

(1-x)²=1²-2x+x² = 1-2x+x²

(2-x)²= 2²-4x+x² = 4-4x+x²

E(x)=(x²-2x+1)-(x²-4x+4)+(1-2x+x²)-(4-4x+x²)

E(x) = x²-2x+1-x²+4x-4+1-2x+x²-4+4x-x²

E(x)=4x+1-4+1-4

E(x)=4x-3+1-4

E(x)=4x-2-4

E(x)=4x-6 ✔