Question

E URGENT
a+b = 65 3a-b/2= 48 plssss

Answer 1

a+b=65
(3a-b)/2=48 => 3a-b=2*48=96

fac un sistem din ecuatiile : 
a+b=65
3a-b=96
__________ adun ambele ecuatii si obtin:

4a = 161 => a=161/4
b=65-161/4=(260-161)/4=99/4

a=161/4
b=99/4

Answer 2

a+b=65   ;  a=65-b
3a-b/2 =48
3( 65-b ) -b/2 =48   
195-3b  -b/2 =48  numitor  2
390-6b -b =96
7b =390-96
7b =294
b =42
a =65-42
a =23
verif  ;   3*23-42/2 =69-21 =48