Question

E URGENT! DAU COROANA!!!​ De la 24 pana la 27

Answer 1

Răspuns:

24. a) $\frac{3}{4}+(\frac{1}{2}) ^{2} =\frac{3}{4}+\frac{1}{4} =1$

b) $5-(\frac{5}{6})^{2}=5-\frac{25}{36} =\frac{180-25}{36}=\frac{155}{36}$

c) $\frac{6}{7}-(\frac{1}{10})^{3} =\frac{6}{7} -\frac{1}{1000} =\frac{6000-7}{7000}=\frac{5993}{7000}$

25. a) x²⁰·x³⁴=x²⁰⁺³⁴=x⁵⁴=$(\frac{5}{6})^{54}$

b) x³⁴:x²⁰=x⁴³⁻²⁰=x¹⁴=$(\frac{5}{6})^{14}$

c) (x²⁰)³⁴=x²⁰*³⁴=x⁶⁸⁰=$(\frac{5}{6})^{680}$

26. a) $(\frac{3}{7}) ^{2} =\frac{9}{47}$

b) $(\frac{5}{9}) ^{0} =1$

c) $(\frac{2}{5}) ^{2} *10-\frac{7}{5} =\frac{40}{25} -\frac{7}{5}=\frac{40-35}{25}=\frac{5}{25} =\frac{1}{5}$

27. a) $(\frac{3}{2}) ^{2} =\frac{2)9}{4}=\frac{18}{8}$         $(\frac{3}{2}) ^{3} =\frac{27}{8}$       $\frac{18}{8} <\frac{27}{8}$ ⇒ $(\frac{3}{2}) ^{2} <(\frac{3}{2}) ^{3}$

b) $(\frac{1}{10}) ^{2} =\frac{10)1}{100}=\frac{10}{1000}$         $(\frac{1}{10}) ^{3} =\frac{1}{1000}$       $\frac{10}{1000} >\frac{1}{1000}$ ⇒ $(\frac{1}{10}) ^{2} >(\frac{1}{10}) ^{3}$

c) $\frac{5}{5} =1$   1²=1   1³=1    1=1 ⇒ 1²=1³

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