Question

E(x)=2x^2-18/x^2+6x+9÷10(x-3)/5x+15

Answer 1

[tex]E(x)=\dfrac{2x^2-18}{x^2+6x+9}:\dfrac{10(x-3)}{5x+15}\\ E(x)=\dfrac{2(x^2-9)}{(x+3)^2}\cdot \dfrac{5(x+3)}{10(x-3)}\\ E(x)=\dfrac{2(x-3)(x+3)}{(x+3)^2}\cdot \dfrac{x+3}{2(x-3)}\\ \text{Dupa ce simplificam obtinem ca }\boxed{E(x)=1} [/tex]