Question

E(x)=$\frac{2 x^{2}+9 }{ x^{2} -9} - \frac{3}{(x+3)(x-3)} - \frac{ x^{2} -x-6}{ x^{2} -6x+9}$
Sa se aduca la forma cea mai simpla. 

Answer 1

E(x)=E(x)=[(2x²+9)/(x+3)(x-3)}-[3/(x+3)(x-3)]-[(x+2)(x-3)/(x-3)(x-3)]
E(x)=[(2x²+9-3)/(x+3)(x-3)]-[(x+2)/(x-3)]
E(x)=[(2x+6)-(x+2)(x+3)]/(x-3)(x+3)
E(x)={2x+6-(x²+3x+2x+6)]/(x-3)(x+3)
E(x)=(2x+6-x²-5x-6)/(x+3)(x-3)
E(x)=(-x²-3x)/(x-3)(x+3)
E(x)=-x(x+3)/(x-3)(x+3)
E(x)=-x/x-3)