Question

E(x) = $\frac{ x^{2} }{ x^{2} + 1}$ si F(x) = $\frac{1}{ x^{2} + 1}$

Aratati ca F(-2) = E ($- \frac{1}{2} )$ . 

Inlocuim si calculam, insa nu stiu daca am obtinut corect sau daca am rezolvat corect exercitiul. Va rog, ajutati-ma! Mercii! 

Answer 1

x²/(x²+1)
E(-1/2)=(-1/2)²  /(-1/2)²+1 =(1/4) /[(1/4)+1]=(1/4)/[(1+4)/4]=1/4x4/5=1/5

1/(x²+1)
F(-2)=1/[(-2)²+1 =1/5
deci E(-1/2)=F(-2)