Question

E(x)=(x+2)²-9/x2-25 : x-1/x-5

Answer 1

[tex]E(x) = \frac{(x+2)^2}{x^2-25} : \frac{x-1}{x-5} [/tex]

$E(x) = \frac{(x+2-3)(x+2+3)}{(x-5)(x+5)} * \frac{x-5}{x-1}$

$E(x) = \frac{(x-1)(x+5)}{x+5} * \frac{1}{x-1}$

$E(x) = 1$