Question

E x = (x-3)² + 2(3+x)(x-3) - (x-2)² - ( x-1)(1+x)​

Answer 1

Răspuns:

$\displaystyle{ E(x) = x^{2} -10x - 12 }$

Explicație pas cu pas:

$\displaystyle{ E(x) = (x-3)^{2} + 2(3+x)(x-3) - (x-2)^{2}-(x-1)(1+x) }$

$\displaystyle{ E(x) = x^{2} - 6x + 9+2\cdot(x^{2} - 9) - (x^{2}-4x+4)-(x^{2}-1) }$

$\displaystyle{ E(x) = x^{2} - 6x + 9+2x^{2}-18-x^{2}+4x-4-x^{2}+1 }$

$\displaystyle{ E(x) = x^{2} + 2x^{2} - x^{2} - x^{2} -6x +4x + 9 - 18 - 4 + 1 }$

$\displaystyle{ E(x) = x^{2} \cdot (1+2-1-1) - x \cdot (6 + 4) -9 -4 + 1 }$

$\displaystyle{ E(x) = x^{2} \cdot 1 - 10x -13 + 1 }$

$\displaystyle{ E(x) = x^{2} -10x - 12 }$