Question

E(x)= (x-6/ x^2-25 + x/x-5 - 2/ x+5) : 2x^2+x-6/x^2-25 xapartine lui R\ {-5;5} REPEDEE VA ROG DAU CORONITA

Answer 1

E(x)= [(x-6)/ (x²-25) + x/(x-5) - 2/) x+5)] : (2x²+x-6)/(x²-25 ) =
= (x-6+x²+5x-2x+10)/ (x-5)(x+5)  × (x-5)(x+5)/(2x²+4x-3x-6) =
= (x²+4x+4)/[2x(x+2)-3(x+2) =
= (x+2)²/(x+2)(2x-3) =
= (x+2)/(2x-3)