Question

E(x) = ( x la a doua - 2 supra x la a 3) + (3 -2x supra x la a 3 ) * x

Answer 1

······$[tex]\frac{ x^{2}-2 }{ x^{3} } + \frac{3-2x}{ x^{3} }$ * x ( x^{3} se simplifica cu x)[/tex]
$\frac{ x^{2}-2 }{ x^{3} } + \frac{3-2x}{ x^{2} }$ 
$\frac{ x^{2}-2 }{ x^{3} } + \frac{3-2x}{ x^{2} } (fractia 3-2x  pe x la a doua   se amplifica cu x)$
$\frac{ x^{2} -2+x *(3-2x )}{ x^{3} }$
$[<span>\frac{ x^{2} -2+3x-2 x^{2} }{ x^{3} }</span>$
$\frac{ -x^{2} -2+3x }{ x^{3} }$