Question

E(x)=x²-5x+6 pe x²-6x+9
xeR={3}
demonstrati ca E(x)=x-2 pe x-3

Answer 1

$E= \frac{ x^{2} -5x+6}{ x^{2} -6x+9} = \frac{(x-2)(x-3)}{(x-3) ^{2} } =\frac{x-2}{x-3 }$