Question

E(x,y)=(x-4)(x-2)+(y-1)(y-3)+3
x,y apartin R
Demonstrati ca E(x,y)>sau = 1

Answer 1

Răspuns:

E(x,y)=(x-4)(x-2)+(y-1)(y-3)+3

x,y € R

E(x, y) =x^2-2x-4x+8+y^2-3y-y+3+3

E(x,y)= x^2-6x+8+y^2-4y+6

E(x,y)= x^2-6x+14+y^2-4y

E(x,y)= x(x-6)+y(y-4)+14

E(x, y) >=1

x^2-6x+14+y^2-4y>=1

14>=1

Adevarat

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