Question

E(x,y)=x² + y² + 4x - 6y + 13=0, aflati x si y.

Answer 1

     
$E(x, y)= x^{2} + y^{2} +4x-6y+13=0 \\ x^{2} + y^{2} +4x-6y+4+9=0 \\ x^{2} +4x +4+ y^{2} -6y+9=0 \\ (x^{2} +4x +4)+ (y^{2} -6y+9)=0 \\ (x^{2} +2*2x +2^2)+ (y^{2} -2*3y+(-3)^2)=0 \\ (x+2)^2(y-3)^2=0 \\ (x+2)^2=0\;\;\;=\ \textgreater \ \;\;\;\boxed{x_1=-2\;\;\;si\;\;\;x_2=-2 } \\ (y-3)^2=0 \;\;\;=\ \textgreater \ \;\;\;\boxed {y_1=3\;\;\;si\;\; y_2=3 }$