Question

ecuati de forma x^2=a,unde a apartine Q
EX: 1)Rezolvati ecuatia:  x^2+(x+2)^2+(x+4)^2=4(3x+8)
EX:  2) Determinati x apartine R pentru care (3x+4)^2=(2x+1)^2

Answer 1

x²+x²+4x+4+x²+8x+13=12x+32
3x²+20=32
3x²=12
x²=4
x=+sau-2


b) 3x+4=2x+1 ( bazele sunt egale daca exponentii sunt egali)
3x-2x=1-4
x=-3