Question

ecuatia de gradul2 x la patrat+2x+1

Answer 1

$x^{2} +2x+1=$

a=1
b=2
c=1

Δ=$b^{2} -4ac$
  = 4-4
  =0
$\sqrt{}$Δ=0

$x_{1}= \frac{-b- \sqrt{delta} }{2a}= \frac{-2-0}{2}= \frac{-2}{2}$=-1$[tex] x_{2}= \frac{-b+ \sqrt{delta} }{2a}= \frac{-2+0}{2}= -\frac{2}{2}=-1$

⇒ $x^{2} +2x+1=(x+1)(x+1)= (x+1)^{2}$

Δ=delta