Question

ecuatia din poza (e cu sens invers)

Answer 1

( $\frac{6}{5}$x - $\frac{7}{3}$ ) * $\frac{9}{10}$ -$\frac{1}{5}$ = $\frac{1}{2}$ * $\frac{13}{5}$

( $\frac{6}{5}$x - $\frac{7}{3}$ ) * $\frac{9}{10}$ =  $\frac{13}{10}$ + $\frac{1}{5}$

( $\frac{6}{5}$x - $\frac{7}{3}$ ) * $\frac{9}{10}$ = $\frac{15}{10}$
( $\frac{6}{5}$x - $\frac{7}{3}$ ) = $\frac{15}{10}$ :  $\frac{9}{10}$

( $\frac{6}{5}$x - $\frac{7}{3}$ ) =  $\frac{15}{10}$ * $\frac{9}{10}$

( $\frac{6}{5}$x - $\frac{7}{3}$ ) = $\frac{15}{9}$

$\frac{6}{5}$x  = $\frac{5}{3}$ + $\frac{7}{3}$ )

$\frac{6}{5}$x =  $\frac{12}{3}$

$\frac{6}{5}$x=4

x=4:$\frac{6}{5}$
x=4* $\frac{5}{6}$
x=$\frac{10}{3}$