Question

ecuatie de gradul 2: 3x^2 -x-2=0

Answer 1

3x²-x-2=0
a=3
b=-1
c=-2
Δ=b²-4ac⇒Δ=1+24⇒Δ=25⇒√Δ=√Δ25⇒Δ=5
x1x2=-b+-√Δ/2a⇒
x1=1+5/6⇒6/6⇒x1=1
x2=1-5/6⇒-4/6⇒se simplifica prin2⇒-2/3
sucees

Answer 2

   
[tex]\displaystyle \\ 3x^2 -x-2=0 \\ \\ \texttt{Folosim formula: } x_{12}= \frac{-b \pm \sqrt{b^2-4ac} }{2a} \\ \\ \texttt{Rezolvare: } \\ \\ x_{12}= \frac{1 \pm \sqrt{1-4\cdot 3 \cdot (-2)} }{2\cdot 3}= \frac{1 \pm \sqrt{25} }{6}=\frac{1 \pm 5 }{6} \\ \\ x_1 = \frac{1 + 5 }{6} = \frac{6 }{6}=\boxed{1} \\ x_2 = \frac{1 - 5 }{6} = \frac{-4 }{6}=\boxed{- \frac{2}{3} } [/tex]