Question

ecuatie de gradul 2:
3xla a 2-4x=0
2xlaa 2-72=0
2xla a 2 -5x-3=0

Answer 1

[tex]\it 3x^2 -4x = 0 \Longleftrightarrow x(3x-4)=0\Longleftrightarrow \begin{cases} \it x=0 \\ \it 3x-4=0 \Rightarrow x=\dfrac{4}{3}\end{cases} [/tex]

b)

[tex]\it 2x^2 -72 =0 \Leftrightarrow 2(x^2-36)=0 |_{:2} \Leftrightarrow x^2-36=0 \Leftrightarrow x^2-6^2=0 \\\;\\ \Leftrightarrow \it (x-6)(x+6)=0 \Leftrightarrow \begin{cases} x+6=0 \Rightarrow x=-6 \\ x-6=0 \Rightarrow x=6 \end{cases} \\ .[/tex]