Question

Ecuatie de gradul 2
x(x+1)(x+2)(x+3)=24

Answer 1

x(x+1)(x+2)(x+3)=24=> x(x+3)*(x+1)(x+2)=24=>
 (x^{2} +3x)*(( x^{2} +3x)+2)= 24 => 
(x^{2} +3x)^{2} +2*( x^{2} +3x)=24 
Notam t= x^{2} +3x=> t^{2} +2t=24 => $t^{2} +2t-24=0$