Question

Efectiati: [(3²)⁵:3⁷-3⁰-3²]×4÷32+2² b)[123+2⁷×2²+2⁶⁷:2²⁷]:[123+2¹⁴:2⁵+(2⁵)⁸] c) (25⁴)³:(4²+3²)¹¹-(0²⁰¹⁰+1²⁰¹²+2013⁰)² VA ROGGG DAU COROANAAAAAA​

Answer 1

Răspuns:

[(3²)⁵:3⁷-3⁰-3²]×4÷32+2² =

(3²ˣ⁵:3⁷-1-9)·4:32+4=

(3¹⁰⁻⁷-1-9)·4:32+4=

(27-1-9)·4:32+4=

17·4:32+4=

68:32+4=2,125+4=6,125

__________

b)[123+2⁷×2²+2⁶⁷:2²⁷]:[123+2¹⁴:2⁵+(2⁵)⁸]=

(123+2⁷⁺²+2⁶⁷⁻²⁷):(123+2¹⁴⁻⁵+2⁵ˣ⁸)=

(123+2⁹+2⁴⁰):(123+2⁹+2⁴⁰)=1

__________

c) (25⁴)³:(4²+3²)¹¹-(0²⁰¹⁰+1²⁰¹²+2013⁰)²=

25⁴ˣ³:(25)¹¹-(0+1+1)²=

25¹²⁻¹¹-2²=25¹-4=21

Answer 2

Răspuns:

Explicație pas cu pas:

[(3²)⁵: 3⁷ - 3⁰ - 3² ] × 4 : 32 + 2² =

= ( 3²ˣ⁵ : 3⁷ - 1 - 9 ) × 4 : 32 + 4 =

= ( 3¹⁰⁻⁷ - 1 - 9 ) × 4 : 32 + 4 =

= ( 3³ - 10 ) × 4 : 32 + 4 =

= ( 27 - 10 ) × 4 : 32 + 4 =

= 17 × 4 : 32 + 4 =

= 68 : 32 + 4 =

= 2,125 + 4 =

= 6,125

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b)

[123 + 2⁷×2² + 2⁶⁷ : 2²⁷] : [123 + 2¹⁴ : 2⁵ + (2⁵)⁸] =

= ( 123 + 2⁷⁺² + 2⁶⁷⁻²⁷ ) : ( 123 + 2¹⁴⁻⁵ + 2⁵ˣ⁸ ) =

= ( 123 + 2⁹ + 2⁴⁰) : ( 123 + 2⁹ + 2⁴⁰) =

= 1

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c)

(25⁴)³ : (4² + 3²)¹¹ - ( 0²⁰¹⁰ + 1²⁰¹² + 2013⁰)² = 21

= 25⁽⁴ˣ³⁾ : ( 16 + 9)¹¹ - ( 0 + 1 + 1 )² =

= 25¹² : 25¹¹ - 2² =

= 25⁽¹²⁻¹¹⁾ - 4 =

= 25¹ - 4 =

= 21