Question

efectuând calculele (3supra2+4supra3+5supra4)^2×(2supra4-1supra4-1supra6-1supra12)obținem rezultatul​

Answer 1

(3/2 + 4/3 + 5/4)² × (2/4 - 1/4 - 1/6 - 1/12) = ?

(3/2 + 4/3 + 5/4)² = (49/12)²

(2/4 - 1/4 - 1/6 - 1/12) = 1/4 - 1/6 - 1/12 = 3/12 - 2/12 - 1/12 = 0/12 = 0

ne rămâne :

(49/12)² × 0 = 0

Succes ! =)