Question

efectuand calculele indicate obtinem ca numarul a = √4 intregi 37 pe 81 + √2 intregi 1 pe 144. - √4 intregi 25 pe 36 are valoarea

Answer 1

4 37/81=361/81
2 1/144=289/144
4 25/36=169/36
√361/81+√289/144-√169/36=
=19/9+17/12-13/6=
=(19×4+17×3-13×6)/36=
=(76+51-78)/36=
=49/36= 1 intregi 13/36 =1,36(1)