Question

efectuati
0,3·2y+1,6·5y-1,2·0,5y= ?
3a²·0,7b+1,5a·1,2ab-2,8ab·4a
1,8a²:(3a)-2,5a la apatra :(5a³)+0,3·(-2a)
dau coroana si multumire

Answer 1

rezolvarea in poza:)))

Answer 2

0,3·2y+1,6·5y-1,2·0,5y=3/10·2y+16/10·5y-12/10·5/10y=
=3/5y+8y-3/5y=40y/5=8y
3a²·0,7b+1,5a·1,2ab-2,8ab·4a=3a²·7/10b+15/10a·12/10ab-28/10ab·4a=
=21a²b/10+18a²b/10-112a²b/10=-73a²b/10
1,8a²÷(3a)-2,5a^4÷(5a³)+0,3·(-2a)=18/10a²÷3a-25/10a^4÷5a³+3/10·(-2a)=
=6a/10-5a/10-6a/10=-5a/10=-2a