Efectuati: (1\2+2^40):[(2\3)^40:(1-2\3)^39+2^40\3:2^41]
FACETI REZOLVAREA FRUMOASA.
renatemambouko:
verifica dca e scris corect
ok
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(1/2+2⁴⁰):[(2/3)⁴⁰:(1-2/3)³⁹+2⁴⁰/3:2⁴¹]=
=(1+2⁴¹)/2:[(2/3)⁴⁰:(1/3)³⁹+1/6]=
=(1+2⁴¹)/2:[(2⁴⁰/3+1/6]=
=(1+2⁴¹)/2:[(2⁴⁰×2+1)/6]=
=(1+2⁴¹)/2 ×6/(2⁴¹+1)=
=6/2=3
=(1+2⁴¹)/2:[(2/3)⁴⁰:(1/3)³⁹+1/6]=
=(1+2⁴¹)/2:[(2⁴⁰/3+1/6]=
=(1+2⁴¹)/2:[(2⁴⁰×2+1)/6]=
=(1+2⁴¹)/2 ×6/(2⁴¹+1)=
=6/2=3
ok
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